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We can solve this puzzle with three sudoko techniques.

First with Naked Pair (already @Glorfindel discussed). This one will fit with column $6^{th}$, where $2$ and $9$ will follow the naked pair, and remaining $2$ and $9$ from column $6^{th}$ would be eliminated.

second with Naked Triple, where $2$, $3$ and $4$ fit for the naked triple of row $5$. Then we will eliminate $4$ from $R5C4$ and $8$ and $9$ from $R5C7$.

third with XY Wing : $R6C1$, $R5C4$, and $R8C6$ fit for the XY Wing technique. Here we need to assume $8$ or $9$ of $R5C4$, where we assumed $8$ and this assumption fit properly (if we assume $9$, it will not fit properly).

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After assuming $8$ of $R5C4$, then the solution would be simple. Final solution looks like.

We can solve this puzzle with two sudoko techniques.

First with Naked Pair (already @Glorfindel discussed). This one will fit with column $6^{th}$, where $2$ and $9$ will follow the naked pair, and remaining $2$ and $9$ from column $6^{th}$ would be eliminated.

second with XY-Wing, where R6C5, R7C3 and R7C6 fit for the XY-wing technique. We will choose $7$ from R6C5, and this number will fit (other number $2$ from R6C5 will not fit here). Please see the below in the picture.

Final solution looks like.

We can solve this puzzle with three sudoko techniques.

First with Naked Pair (already @Glorfindel discussed). This one will fit with column $6^{th}$, where $2$ and $9$ will follow the naked pair, and remaining $2$ and $9$ from column $6^{th}$ would be eliminated.

second with Hidden Triple, where $2$, $3$ and $4$ fit for the hidden triple of row $5$. Then we will eliminate $4$ from $R5C4$ and $8$ and $9$ from $R5C7$.

third with XY Wing : $R6C1$, $R5C4$, and $R8C6$ fit for the XY Wing technique. Here we need to assume $8$ or $9$ of $R5C4$, where we assumed $8$ and this assumption fit properly (if we assume $9$, it will not fit properly).

.

After assuming $8$ of $R5C4$, then the solution would be simple. Final solution looks like.

We can solve this puzzle with three sudoko techniques.

First with Naked Pair (already @Glorfindel discussed). This one will fit with column $6^{th}$, where $2$ and $9$ will follow the naked pair, and remaining $2$ and $9$ from column $6^{th}$ would be eliminated.

second with Naked Triple, where $2$, $3$ and $4$ fit for the naked triple of row $5$. Then we will eliminate $4$ from $R5C4$ and $8$ and $9$ from $R5C7$.

third with XY Wing : $R6C1$, $R5C4$, and $R8C6$ fit for the XY Wing technique. Here we need to assume $8$ or $9$ of $R5C4$, where we assumed $8$ and this assumption fit properly (if we assume $9$, it will not fit properly).

.

After assuming $8$ of $R5C4$, then the solution would be simple. Final solution looks like.

We can solve this puzzle with three sudoko techniques.

First with Naked Pair (already @Glorfindel discussed). This one will fit with column $6^{th}$, where $2$ and $9$ will follow the naked pair, and remaining $2$ and $9$ from column $6^{th}$ would be eliminated.

second with Hidden Triple, where $2$, $3$ and $4$ fit for the hidden triple of row $5$. Then we will eliminate $4$ from $R5C2$ and $8$ and $9$ from $R5C7$.

third with XY Wing : $R6C1$, $R5C4$, and $R8C6$ fit for the XY Wing technique. Here we need to assume $8$ or $9$ of $R5C4$, where we assumed $8$ and this assumption fit properly (if we assume $9$, it will not fit properly).

.

After assuming $8$ of $R5C4$, then the solution would be simple. Final solution looks like.

We can solve this puzzle with three sudoko techniques.

First with Naked Pair (already @Glorfindel discussed). This one will fit with column $6^{th}$, where $2$ and $9$ will follow the naked pair, and remaining $2$ and $9$ from column $6^{th}$ would be eliminated.

second with Hidden Triple, where $2$, $3$ and $4$ fit for the hidden triple of row $5$. Then we will eliminate $4$ from $R5C4$ and $8$ and $9$ from $R5C7$.

third with XY Wing : $R6C1$, $R5C4$, and $R8C6$ fit for the XY Wing technique. Here we need to assume $8$ or $9$ of $R5C4$, where we assumed $8$ and this assumption fit properly (if we assume $9$, it will not fit properly).

.

After assuming $8$ of $R5C4$, then the solution would be simple. Final solution looks like.