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I got to ask this question idea from when try to solve Simple Math Problem.

Here is a simple math problem. Can you solve it?

Examples:

  • $678 + 57 - 24 \times 2 = 3$
  • $265 + 34 - 12 \times 3 = 1$
  • $328 + 58 - 22 \times 1 = 4$

Problem:

$541 + 13 - 21 \times 0 =\; ?$

Hint 01:

Don't think too much... Even grade 5 , 6 student can solve this problem but think outside of the box.

Update

Hint 02:

Answer is "undefined". Find how answer become "undefined".....

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  • $\begingroup$ Not a bad puzzle, but you should really rethink your tags. Just a math tag by itself is not a good fit and will have people searching in the wrong direction(and then raging when they find out what kind of answer it was). And if adding tags gives the solution away too easily, then some strong hints toward the kind of puzzle this is into your question. $\endgroup$
    – stack reader
    Dec 15, 2017 at 4:34
  • $\begingroup$ @stackreader Thanks. I am new to here. So what is the best tag for this type of questions? $\endgroup$
    – I am the Most Stupid Person
    Dec 15, 2017 at 4:37
  • $\begingroup$ @stackreader And Varlam Dadiani's answer is not the answer what I thought when creating this question. Even it is a valid answer, there is a another answer which related to basic maths with outside of the box thinking $\endgroup$
    – I am the Most Stupid Person
    Dec 15, 2017 at 4:39
  • $\begingroup$ Outside of the box thinking usually requires "lateral thinking" tag $\endgroup$
    – stack reader
    Dec 15, 2017 at 4:44

3 Answers 3

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Seriously? I spent all the time just for that?! Great job man... Definitely blessed with some brains ;)

Answer is:

undefined as per link
because well, $x/0 = undefined$. In this specific example, I think the entire equation would be $541 - 13 + 21 / 0$.

Explanation:

Important: Division before addition!
Reverse the sign, plus the numbers, then plus the solution's numbers.

$$ 678 + 57 - 24 \times 2 \\ = 678 - 57 + 24/2 \\ = 678 - 57 + 12 \\ = 21 - 12 + 3 \\= 12 \\= 3 $$
$$265 + 34 - 12 \times 3 \\ = 265 - 34 + 12 / 3 \\ = 265 - 34 + 4 \\ = 13 - 7 + 4 \\= 6 + 4 \\= 10 \\= 1 $$
$$328 + 58 - 22 \times 1 \\= 328 - 58 + 22/1 \\= 328 - 58 + 22 \\= 13 - 13 + 4 \\= 0 + 4 \\= 4$$

Explanation #2:

enter image description here
Plus the numbers and reverse the sign.

$(2+4) / 2 = 6/2 = 3$
$(1+2) / 3 = 3/3 = 1$
$(2+2) / 1 = 4/1 = 4$

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  • $\begingroup$ Your answer also valid.... But No, First numbers also related to this...... But same concept (undefined as per link Because 3/0 = undefined... This is correct)... But you are not allowed to remove other numbers. :-) $\endgroup$
    – I am the Most Stupid Person
    Dec 15, 2017 at 4:42
  • $\begingroup$ @IamtheMostStupidPerson :( lol $\endgroup$
    – Chris Happy
    Dec 15, 2017 at 4:43
  • $\begingroup$ @chirs +1 however great work friend,,, simply it means there are more solutions for problems. $\endgroup$
    – I am the Most Stupid Person
    Dec 15, 2017 at 4:44
  • $\begingroup$ You are in very very close to this question... "Plus the numbers and reverse the sign. " one part also correct in this sentence tooo... awesome... Not both... Just one part... $\endgroup$
    – I am the Most Stupid Person
    Dec 15, 2017 at 4:46
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    $\begingroup$ @ChrisHappy Great work. You got it $\endgroup$
    – I am the Most Stupid Person
    Dec 15, 2017 at 5:49
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The answer is:

1

Explanation:

you are counting circles in numbers.

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    $\begingroup$ Not sure why this is getting downvoted. Seems like a very valid answer to me. Maybe it'll help if you elaborate more on what you mean by circles and how it applies to the examples shown $\endgroup$
    – votbear
    Dec 14, 2017 at 8:06
  • $\begingroup$ Nitpicking: The eight doesn't really have circles, more like teardrop shapes. (I wasn't the one to downvote) $\endgroup$
    – Lolgast
    Dec 14, 2017 at 8:08
  • $\begingroup$ I thought of this one too - but it seemed too arbitrary to be correct $\endgroup$
    – Wen1now
    Dec 14, 2017 at 8:13
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    $\begingroup$ But 4's dont count? $\endgroup$
    – Tweakimp
    Dec 14, 2017 at 8:26
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    $\begingroup$ I believe Varlam was simply counting the circles in total, not performing any arithmetic on the number of individual circles in each number $\endgroup$
    – Adam
    Dec 14, 2017 at 18:39
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It could be(got idea from Varlam Dadiani's answer and Daniel Duque's comment :P)

0

Explanation

count circles in each number, then calculate mathematic equation using this count as numbers

Result

678+57−24×2=3 => 3+0-0 = 3 //(circle in 6 and 8) So 541+13−21×0=? => 0+0-0 = 0

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