5
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See if you can solve this math-problem:

$$ \begin{bmatrix} 1&+&1&=&0\\ 2&+&8&=&2\\ 2&+&2&=&0\\ 9&+&8&=&3\\ 3&+&4&=&0\\ 6&+&9&=&2\\ 0&+&2&=&1\\ 9&+&3&=&? \end{bmatrix} $$

Best of Luck!

Ps: Here is the link without brakets and here is one without latex

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  • $\begingroup$ If you can't see the $\LaTeX$(latex) commands It is here in normal symbols: $\endgroup$
    – math scat
    Jul 23, 2020 at 11:20
  • $\begingroup$ 1+1=0 2+8=2 2+2=0 9+8=3 3+4=0 6+9=2 0+2=1 9+3=? $\endgroup$
    – math scat
    Jul 23, 2020 at 11:22
  • $\begingroup$ $1+1=0\\2+8=2\\2+2=0\\9+8=3\\3+4=0\\6+9=2\\0+2=1\\9+3=?$ $\endgroup$
    – math scat
    Jul 23, 2020 at 11:24
  • 1
    $\begingroup$ I'm sure I've seen this idea on this site before but can't find the dup. $\endgroup$
    – hexomino
    Jul 23, 2020 at 11:35
  • 1
    $\begingroup$ @hexomino This is the closest I've been able to find - quite a different question using the same general concept at its core. Not convinced it's close enough for a dup... $\endgroup$
    – Stiv
    Jul 23, 2020 at 11:47

2 Answers 2

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The answer is:

$$9+3=1$$
In each case, what's being added together here is the number of 'closed counters' (i.e. the 'holes' in the numbers) when the numbers are written out on a standard 7-segment calculator display1. The digit 9 has one closed counter, while 3 has zero. The sum is thus 1.

1 This should rule out any queries surrounding the number '4', which can be considered to have 1 or 0 closed counters in different typefaces.

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  • $\begingroup$ Yes you are right. $\endgroup$
    – math scat
    Jul 23, 2020 at 11:29
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    $\begingroup$ What about the digit $4$? $\endgroup$ Jul 23, 2020 at 11:29
  • $\begingroup$ Just beat me to it!!! $\endgroup$
    – PDT
    Jul 23, 2020 at 11:30
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    $\begingroup$ Good answer, but then it depends on how one would write the 4, no? Here 3 + 4 = 0, not 1. Maybe that’s just a typo/quirk... (+1) $\endgroup$
    – El-Guest
    Jul 23, 2020 at 11:30
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    $\begingroup$ @JaapScherphuis El-Guest and others: My latest edit should overcome this issue... $\endgroup$
    – Stiv
    Jul 23, 2020 at 11:34
2
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My Math logic


 Since 1+1=0 and 2+2=0, I assume that adding the same number gives me zero.
 We also have 0+2=1, meaning that 0+x=1
 9+3 = ?, but we know that 9+8=3, so we can reach this form
 9+3 = ?
 9+(9+8) = ?
 9+9+8 = 0+8 = 1
 Answer 1
 

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  • $\begingroup$ That's an interesting way of getting the answer without finding the pattern. $\endgroup$ Jul 24, 2020 at 6:10
  • $\begingroup$ Very nice out-of-the-box answer. $\endgroup$
    – math scat
    Jul 24, 2020 at 7:10

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